<p>Regardless of how the voltage is lowered, you aren't delivering the power to the heating elements that they are designed to deliver.  For a resistive heater, the power scales with the square of the voltage.</p>

<p>Delivering 11.4&nbsp;V to the heaters will result in the power being <span class="math-container">$11.4^2/12.0^2 = 0.9025$</span> or 90&nbsp;% of the intended power.</p>

<p>There are two things you could do to increase the power at the heaters.</p>

<ol>
<li>Your voltage is starting out low, which you may be able to increase
at the power supply to 12.0&nbsp;V.</li>
<li>The voltage drop in the 1-meter cables can be reduced by using
shorter cables or larger cross-sectional area conductors.  13 gauge
is not a very heavy wire for low-voltage high-current DC.  I would
suggest 10 gauge, and would prefer 8 gauge.</li>
</ol>

<p>The logic in the controller board should be fine as you are now.  Controller boards include regulators that being the nominal 12&nbsp;V down to the 5&nbsp;V or 3.3&nbsp;V required by the digital logic.  These will automatically adjust for changes in the 12&nbsp;V supply.</p>

<p>To actually answer your question, the permitted voltage drop is application dependent.  As a rule, though, I would suggest that the voltage on the pins of the controller should be 12&nbsp;&plusmn;&nbsp;5&nbsp;%, or from 12.6&nbsp;V to 11.4&nbsp;V.  The voltage you measured should be acceptable if it is the true minimum voltage.</p>

CC BY-SA 4.0
2019-05-09T15:35:53.467Z
2019-05-10T22:23:39.120Z
2019-05-10T22:23:39.120Z
cmm
<p>Per <a href="https://www.calculator.net/voltage-drop-calculator.html?material=copper&amp;wiresize=6.571&amp;voltage=12&amp;phase=dc&amp;noofconductor=1&amp;distance=6&amp;distanceunit=feet&amp;amperes=18&amp;x=34&amp;y=15" rel="nofollow noreferrer">this website</a> it matches the expectations.
Using 13AWG =~ 2.5 mm^2, 18amps, 12volts, 6feet = 2meters (1m back and forth).</p>

<p>Results in 0.4v drop.</p>

CC BY-SA 4.0
2019-05-08T18:53:54.610Z
That calculator is set to use the one way distance
Perplexed Dipole
CC BY-SA 4.0
2019-05-08T18:34:23.680Z
2019-05-08T18:34:23.680Z
Viesturs
<p>My voltage at the controller at max load is ~11.4&nbsp;V 
(heated bed + motors + hotend). Is this normal? </p>

<p>I'm measuring 11.8&nbsp;V at the PSU, so 0.4&nbsp;V -> 5&nbsp;W lost in the wires.</p>

<p>I have a pretty beefy ~2&nbsp;mm diameter copper wire that's ~1&nbsp;m long. Its area is 2.5&nbsp;mm<sup>2</sup>. The diameter with shielding is 3.5&nbsp;mm.</p>

<p>Could there be a bad connection somewhere?</p>

<p>Checked the wire is warm to touch, so looks like it's actually the cause.
Is this normal? Should I go for even bigger wires?</p>

CC BY-SA 4.0
2019-05-08T18:23:34.513Z
Welcome to 3dPrinting.SE! Is the "~2mm" wire size with or without the shielding?
Pᴀᴜʟsᴛᴇʀ2
CC BY-SA 4.0
2019-05-08T18:24:20.813Z
Measure the resistance of your wire and see if this matches up with your other measurements
Perplexed Dipole
CC BY-SA 4.0
2019-05-08T18:29:31.177Z
2.5mm^2 would make it ~13AWG (13AWG being 2.62mm^2). [Per this website](https://www.calculator.net/voltage-drop-calculator.html), you should see no more than 0.055% drop in voltage over 1m length at 12vdc, with a pair of wires at the size you are talking. I'd suggest *at least* replace the wiring, if even with the same size. There's some resistance going on there.
Pᴀᴜʟsᴛᴇʀ2
CC BY-SA 4.0
2019-05-08T18:29:34.613Z
Measuring resistance that's <0.1Ohm is tricky.
Viesturs
CC BY-SA 4.0
2019-05-10T18:50:51.667Z
how do you know that 0.4v equates to 5 watts? are there really 12 amps?
dandavis
<wiring>
What is acceptable voltage drop from PSU to controller?
Viesturs
# What is acceptable voltage drop from PSU to controller?

(Asked by: username_0 on 2019-05-08)

My voltage at the controller at max load is ~11.4 V
(heated bed + motors + hotend). Is this normal?

I'm measuring 11.8 V at the PSU, so 0.4 V -> 5 W lost in the wires.

I have a pretty beefy ~2 mm diameter copper wire that's ~1 m long. Its area is 2.5 mm2. The diameter with shielding is 3.5 mm.

Could there be a bad connection somewhere?

Checked the wire is warm to touch, so looks like it's actually the cause.
Is this normal? Should I go for even bigger wires?

**Tags:** wiring
> **Comments:**
> **username_1**: Welcome to 3dPrinting.SE! Is the "~2mm" wire size with or without the shielding?  
> **username_2**: Measure the resistance of your wire and see if this matches up with your other measurements  
> **username_1**: 2.5mm^2 would make it ~13AWG (13AWG being 2.62mm^2). [Per this website](https://www.calculator.net/voltage-drop-calculator.html), you should see no more than 0.055% drop in voltage over 1m length at 12vdc, with a pair of wires at the size you are talking. I'd suggest *at least* replace the wiring, if even with the same size. There's some resistance going on there.  
> **username_0**: Measuring resistance that's <0.1Ohm is tricky.  
> **username_3**: how do you know that 0.4v equates to 5 watts? are there really 12 amps?  

---

## 2 answers

### Answer by username_4 on 2019-05-09. Score: 2

Regardless of how the voltage is lowered, you aren't delivering the power to the heating elements that they are designed to deliver. For a resistive heater, the power scales with the square of the voltage.

Delivering 11.4 V to the heaters will result in the power being $11.4^2/12.0^2 = 0.9025$ or 90 % of the intended power.

There are two things you could do to increase the power at the heaters.

1. Your voltage is starting out low, which you may be able to increase
   at the power supply to 12.0 V.
2. The voltage drop in the 1-meter cables can be reduced by using
   shorter cables or larger cross-sectional area conductors. 13 gauge
   is not a very heavy wire for low-voltage high-current DC. I would
   suggest 10 gauge, and would prefer 8 gauge.

The logic in the controller board should be fine as you are now. Controller boards include regulators that being the nominal 12 V down to the 5 V or 3.3 V required by the digital logic. These will automatically adjust for changes in the 12 V supply.

To actually answer your question, the permitted voltage drop is application dependent. As a rule, though, I would suggest that the voltage on the pins of the controller should be 12 ± 5 %, or from 12.6 V to 11.4 V. The voltage you measured should be acceptable if it is the true minimum voltage.


---

### Answer by username_0 on 2019-05-08. Score: 0

Per [this website](https://www.calculator.net/voltage-drop-calculator.html?material=copper&wiresize=6.571&voltage=12&phase=dc&noofconductor=1&distance=6&distanceunit=feet&eres=18&x=34&y=15) it matches the expectations.
Using 13AWG =~ 2.5 mm^2, 18amps, 12volts, 6feet = 2meters (1m back and forth).

Results in 0.4v drop.

> **Comments:**
> **username_2**: That calculator is set to use the one way distance  

---

