### Godot version

4.0.2.stable.mono

### System information

Windows 10 - 4.0.2.stable.mono - Any Renderer

### Issue description

In a script with an `@export` variable (with a non-default value), Godot will replace the first variable in the category with the same name. For example, if you're exporting a variable called "Vector", and the value is set to a non-default value, the first variable in the category called "Vector" will also be changed to the same value.

### Steps to reproduce

Attach said script to a node:
```
extends Node

@export var Vector: Vector2
@export_category("Vector")
@export var Var2: float = 1

func _process(delta):
	print(Var2)
```
When changing the value of the `Vector` export variable, the variable Var2 will contain the same value. This does not happen when the `@export_category` has a different name.

### Minimal reproduction project

N/A
} else {
				gen->write_construct_array(result, values);
			}
			for (int i = 0; i < values.size(); i++) {
				if (values[i].mode == GDScriptCodeGenerator::Address::TEMPORARY) {
					gen->pop_temporary();
				}
			}
			return result;
		} break;
		case GDScriptParser::Node::DICTIONARY: {
			const GDScriptParser::DictionaryNode *dn = static_cast<const GDScriptParser::DictionaryNode *>(p_expression);
			Vector<GDScriptCodeGenerator::Address> elements;
			
			GDScriptDataType dict_type;
			dict_type.has_type = true;
			dict_type.kind = GDScriptDataType::BUILTIN;
			dict_type.builtin_type = Variant::DICTIONARY;
			GDScriptCodeGenerator::Address result = codegen.add_temporary(dict_type);
			for (int i = 0; i < dn->elements.size(); i++) {
				
				GDScriptCodeGenerator::Address element;
				switch (dn->style) {
					case GDScriptParser::DictionaryNode::PYTHON_DICT:
						
						element = _parse_expression(codegen, r_error, dn->elements[i].key);
						if (r_error) {
							return GDScriptCodeGenerator::Address();
						}
						break;