payload: {"action":"created","issue":{"url":"https://api.github.com/repos/amimo/goron/issues/3","repository_url":"https://api.github.com/repos/amimo/goron","labels_url":"https://api.github.com/repos/amimo/goron/issues/3/labels{/name}","comments_url":"https://api.github.com/repos/amimo/goron/issues/3/comments","events_url":"https://api.github.com/repos/amimo/goron/issues/3/events","html_url":"https://github.com/amimo/goron/issues/3","id":502973844,"node_id":"MDU6SXNzdWU1MDI5NzM4NDQ=","number":3,"title":"string encrypt pass是否有计划","user":{"login":"qtfreet00","id":41325480,"node_id":"MDQ6VXNlcjQxMzI1NDgw","avatar_url":"https://avatars0.githubusercontent.com/u/41325480?v=4","gravatar_id":"","url":"https://api.github.com/users/qtfreet00","html_url":"https://github.com/qtfreet00","followers_url":"https://api.github.com/users/qtfreet00/followers","following_url":"https://api.github.com/users/qtfreet00/following{/other_user}","gists_url":"https://api.github.com/users/qtfreet00/gists{/gist_id}","starred_url":"https://api.github.com/users/qtfreet00/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/qtfreet00/subscriptions","organizations_url":"https://api.github.com/users/qtfreet00/orgs","repos_url":"https://api.github.com/users/qtfreet00/repos","events_url":"https://api.github.com/users/qtfreet00/events{/privacy}","received_events_url":"https://api.github.com/users/qtfreet00/received_events","type":"User","site_admin":false},"labels":[{"id":1556860725,"node_id":"MDU6TGFiZWwxNTU2ODYwNzI1","url":"https://api.github.com/repos/amimo/goron/labels/enhancement","name":"enhancement","color":"a2eeef","default":true}],"state":"open","locked":false,"assignee":null,"assignees":[],"milestone":null,"comments":29,"created_at":"2019-10-05T15:00:02Z","updated_at":"2019-10-17T10:29:06Z","closed_at":null,"author_association":"NONE","body":"目前开源的针对字符串的pass相对来说都是转换成全局变量一次性还原，而非运行到该处时再还原，容易被破解"},"comment":{"url":"https://api.github.com/repos/amimo/goron/issues/comments/543111684","html_url":"https://github.com/amimo/goron/issues/3#issuecomment-543111684","issue_url":"https://api.github.com/repos/amimo/goron/issues/3","id":543111684,"node_id":"MDEyOklzc3VlQ29tbWVudDU0MzExMTY4NA==","user":{"login":"qtfreet00","id":41325480,"node_id":"MDQ6VXNlcjQxMzI1NDgw","avatar_url":"https://avatars0.githubusercontent.com/u/41325480?v=4","gravatar_id":"","url":"https://api.github.com/users/qtfreet00","html_url":"https://github.com/qtfreet00","followers_url":"https://api.github.com/users/qtfreet00/followers","following_url":"https://api.github.com/users/qtfreet00/following{/other_user}","gists_url":"https://api.github.com/users/qtfreet00/gists{/gist_id}","starred_url":"https://api.github.com/users/qtfreet00/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/qtfreet00/subscriptions","organizations_url":"https://api.github.com/users/qtfreet00/orgs","repos_url":"https://api.github.com/users/qtfreet00/repos","events_url":"https://api.github.com/users/qtfreet00/events{/privacy}","received_events_url":"https://api.github.com/users/qtfreet00/received_events","type":"User","site_admin":false},"created_at":"2019-10-17T10:29:06Z","updated_at":"2019-10-17T10:29:06Z","author_association":"NONE","body":"针对这种static const char *xx[]; 和全局可被其它引用的字符串类型，可以单独使用像Armariris这样的混淆方案，虽然容易被破解，但仅仅只对这些类型进行混淆，其它的类型使用你这种方式，这样可以做到全部混淆"}}
other: {"actor":{"display_login":"qtfreet00"}}