Consider the sequence defined as follows: the first term is 2, and each subsequent term is obtained by adding the previous term to the product of its position in the sequence and the term before the previous one. Specifically, if the sequence is \(a_1, a_2, a_3, \ldots\), then the \(n\)-th term is given by \(a_n = a_{n-1} + n \cdot a_{n-2}\). If the 5th term is 41, find the 4th term. Let's think step by step and output the final answer within \boxed{}.
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