SELECT DISTINCT T2.name ,  T2.friend ,  T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name  =  T2.friend WHERE T1.age  >  (SELECT avg(age) FROM person)
Who has friends that are older than the average age? Print their friends and their ages as well
[Schema (values) (types)]: | network_2 |  Person : name (text) , age (text) , city (number) , gender (text) , job (text) | PersonFriend : name (text) , friend (text) , year (number);