SELECT T1.id ,  T1.name FROM browser AS T1 JOIN accelerator_compatible_browser AS T2 ON T1.id  =  T2.browser_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
What is the id and name of the browser that is compatible with the most web accelerators?
[Schema (values) (types)]: | browser_web |  Web_client_accelerator : id (text) , name (number) , operating_system (text) , client (text) , connection (text) | browser : id (text) , name (number) , market_share (text) | accelerator_compatible_browser : accelerator_id (text) , browser_id (number) , compatible_since_year (text);