SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id  =  t3.manufacturer_id WHERE t1.num_of_component  <  6 INTERSECT SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID  =  t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id  =  t3.manufacturer_id WHERE t1.num_of_component  >  10
Find the name of the company that produces both furnitures with less than 6 components and furnitures with more than 10 components.
[Schema (values) (types)]: | manufacturer |  manufacturer : manufacturer_id (text) , open_year (number) , name (number) , num_of_factories (text) , num_of_shops (number) | furniture : furniture_id (text) , name (number) , num_of_component (number) , market_rate (text) | furniture_manufacte : manufacturer_id (text) , furniture_id (number) , price_in_dollar (number);