SELECT DISTINCT T2.Name FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID  =  T2.Mountain_ID WHERE T1.Country  =  "West Germany"
Show the distinct names of mountains climbed by climbers from country "West Germany".
[Schema (values) (types)]: | climbing |  mountain : mountain_id (text) , name (number) , height (text) , prominence (number) , range (number) , country (text) | climber : climber_id (text) , name (number) , country (text) , time (number) , points (number) , mountain_id (text);